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Grammars (1-5): A number and word sorting machine, given an input sequence of numbers and words, rearranges them according to a specific rule at each step. Below is an illustration of the log reconfiguration.
Enter: bread 31 63 break 44 race 24 breath 51
Step I: Bread 31 63 Break 44 Breathe 51 Break 08
Step II: 63 breaks 44 make breath 51 breaks 08 bread 03
Step III: 63 breaths 51 breaks 08 bread 03 breaks 16
Step IV: 63 breaking the race 08 bread 03 breaking 16 breathing 05
Step V: break 08 bread 03 break 16 breath 05 race 18
Step VI: 08 08 04 03 11 16 08 05 04 18
Step VII: 03 04 04 05 08 08 08 11 16 18
And step VII is the last step of the reset. According to the rules followed in the above step, find the appropriate step for the given input for each of the questions below.
Fall: deer 43 87 dead 54 to 23 dear 68
Q1. How many steps are needed to get to the last step?
(a) Six
(b) Seven
(c) Eight
(d) Nine
(e) None of these
Q2. How many elements are there between ‘dead’ and ‘contract’ in stage IV of the given input?
(a) One
(b) Two
(c) Three
(d) Four
(e) None of these
Q3. Which of the following is the fourth step in data entry?
(a) 87 deaths 06 deafness 12 contracts 20 dear 48
(b) 87 deer 12 dead 06 contract 20 dear 48
(c) 87 dead 06 deaf 12 dear 48 contract 20
(d) 87 deaths due to 06 deafness 12 contract 48 dear 20
(e) None of these
Q4. How many words are there between ’06’ and ’56’ in phase V of the given input?
(a) One
(b) Two
(c) Three
(d) Four
(e) None of these
Q5. In which of the following steps will ‘dead 06 kerr 12’ appear in the same row?
(a) Step II
(b) Step III
(c) Step IV
(d) Step V
(e) All of these
Rules (6-9): To answer the questions study the following example according to the relevant conditions given below.
Condition:
I. If the number of vowels in the English alphabetic series between the alphabets in the triangle is 2 or more, then each alphabet of the triangle will be replaced by the second consecutive alphabet.
II. If the number of vowels in the English alphabetic sequence between the triangular alphabets is 1, then each alphabet will be replaced by the second first alphabet.
III. If the multiplication of the two numbers of the triangle is greater than 20, then the number of the triangle is reduced by 8.
IV. If the multiplication of the two digits of the triangle is 20 or less than 20, then the number of the triangle is multiplied by 13.
Given the given conditions, find the output of the given input and answer the following question:
Q6. What is the sum of the digits of the larger number in the two numbers in the input output?
(a) 14
(b) 16
(c) 18
(d) 20
(e) None of these
Q7. How many vowels are there in the given input output?
(a) One
(b) Two
(c) Three
(d) Four
(e) None of these
Q8. How many alphabets are there (according to English alphabetical order) between the second alphabets of the two triangles in the given input output?
(a) Seven
(b) Eight
(c) Six
(d) Four
(e) None of these
Q9. What is the difference between the two numbers in the result?
(a) 26
(b) 27
(c) 25
(d) 23
(e) None of these
Director (10-12): The question below has three outcomes followed by four statements in the options. You must take the four given statements as true even though they appear to be different from commonly known facts and then decide which of these given statements are true regardless of the commonly known facts.
Q10. Result: No Cycle is a bus. Some cars are cars. Some trucks are not two-wheelers.
(a) No auto cycle. Some cars are two-wheelers. Some buses are buses. All buses are trucks.
(b) All buses are buses. Some cars are not bicycles. Some cycles are autos. No bus is a truck.
(c) Some buses are trucks. No car is a bicycle. Some cycles are autos. Some buses are buses.
(d) Some vehicles are two-wheelers. All wheels are buses. There is no bus. All buses are trucks.
(e) None of these
Q11. Result: It may be several minutes to hours. Months are not years. Some days are minutes.
(a) Some minutes are months. All months are days. Some days are years. Years are not hours.
(b) Some minutes are months. Months are not days. Days are not years. All years are hours.
(c) No minutes are months. Some months are days. Days are not years. Some years are hours.
(d) Some minutes are months. All months are days. Days are not years. Some years are hours.
(e) None of these
Q12. Result: No ball is red. Some shoes are black. Some are top baskets.
(a) Some bats are black. Some bats are not shoes. All balls are bats. Some are black and red.
(b) All bats are black. Some bats are shoes. All balls are bats. Not black is red.
(c) You bat is black. Some bats are shoes. All balls are bats. Some are black not red.
(d) Some bats are not black. No bat is a shoe. All balls are bats. All blacks are red.
(e) None of these.
Rule (13-15): The following question has two/three outcomes and four statements in the options. You must take the four given statements as true even though they appear to be different from commonly known facts and then decide which of these given statements are true regardless of the commonly known facts.
Q13. Result: Some shelves are broken. Some tables have shelves. No box is a chair.
(a) Some floors are not boxes. You are a shelf box. Some boxes are tables. Some shelves are chairs.
(b) Some floors are boxes. Some boxes are not shelves. Some boxes are tables. All shelves are chairs.
(c) All floors are boxes. Some boxes are shelves. No box is a table. All shelves are chairs.
(d) Some floors are boxes. All boxes are shelves. Some boxes are tables. No seat shell.
(e) None of these.
Q14. Result: Some fruits are oranges. All bananas are likely to be fruit. An apple is not a mango.
(a) Some oranges are apples. Some apples are bananas. An apple is not a fruit. No fruit is mango.
(b) Some apples are oranges. Some apples are bananas. All bananas are fruits. No fruit is mango.
(c) Some apples are oranges. All apples are fruits. No fruit is mango. Some oranges are bananas.
(d) All oranges are apples. All apples are fruits. Some bananas are fruits. Some fruits are mangoes.
(e) None of these
Q15. Result: Some black is not blue. Some blue is green is a possibility.
(a) Some plants are green. Not red is black. All blacks are green.
(b) All blues are red. Some red is black. All blacks are green.
(c) Not blue is red. All red is black. Not black is green.
(d) Not blue is red. Not red is black. All blacks are green.
(e) None of the above
Solutions
Solution (1-5):
Step 1: The first word goes to the right end according to the English Dictionary order and the multiplication of the two digits of the smallest number follows.
Step II: The second word goes to the right end according to the order of the English Dictionary and the multiplication of the second two digits is followed by the smallest number.
Step III: The third word goes to the right end according to the order of the English Dictionary and the multiplication of the two third numbers is followed by the smallest number.
Step IV: The fourth word goes to the right end according to the order of the English Dictionary and the product of the second two digits is followed by the largest number.
Step V: The fifth word goes to the far right according to the English Dictionary order, followed by the multiplication of the two digits of the largest number.
Step VI: Replace all the words with the numerical value of the last alphabet according to the English alphabetical order.
Step VII: Arrange all the numbers in ascending order from left.
Fall: deer 43 87 dead 54 to 23 dear 68
Step I: deer 43 87 contract 54 because of dear 68 dead 06
Step II: 87 reconciled 54 due to love 68 dead 06 deaf 12
Step III: 87 loved ones 68 dead 06 deaf 12 contracts 20
Step IV: 87 deaths 06 deafness 12 contracts 20 loved ones 48
Step V: dead 06 deaf 12 contract 20 dear 48 to 56
Step VI: 04 06 06 12 12 20 18 48 05 56
Step VII: 04 05 06 06 12 12 18 20 48 56
S1. Ans. (b)
S2. Ans. (c)
S3. Ans. (one)
S4. Ans. (d)
S5. Ans. (is)
Solution (6-10):
In the triangle facing north, we get
3×2 = 6,
6 < 20,
Therefore, we apply condition IV and we get,
32 + 13 = 45.
Therefore, 32 will change to 45.
In the triangle facing south, we get
7 × 6 = 42,
42 > 20,
Therefore, we apply condition III and get,
76 – 8 = 68.
Therefore, 76 will change to 68.
In the triangle facing west, we get
Between d and m there are two vowels (E and I).
Therefore, we apply the condition i and we get,
d + 2 = f; m + 2 = o
Therefore, ‘dm’ will be replaced by ‘fo’.
In the triangle facing east, we get
There is a vowel (U) between q and x.
Therefore, we apply condition II and get,
q – 2 = o; x – 2 = v
Therefore, ‘qx’ will be replaced by ‘ov’.
The final output for the given input is:
S6. Ans. (one)
S7. Ans. (b)
S8. Ans. (c)
S9. Ans. (d)
S10. Ans. (d)
Sol.
S11. Ans. (d)
Sol.
S12. Ans. (b)
Sol.
S13. Ans. (d)
Sol.
S14. Ans. (c)
Sol.
S15. Ans. (c)
Sol.
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